WSOP 2026: Teun Mulder Runner-Up in $100,000 High Roller, Earns $1,894,282
Dutch player Teun Mulder finished runner-up in the $100,000 buy-in high roller event at WSOP 2026, earning approximately $1,894,282. This event was one of the highest buy-in tournaments of the series this year.
According to poker news site Pokeren.nl, the $100,000 buy-in high roller event at the 2026 World Series of Poker (WSOP) has just concluded, with Dutch professional Teun Mulder delivering an impressive performance to finish as runner-up, earning $1,894,282.
This high roller attracted a field of elite poker players, with a buy-in of $100,000, making it one of the highest-stakes events in this year's WSOP series. Although the champion's identity was not disclosed in the report, Mulder's runner-up finish is already highly notable.
Teun Mulder is a rapidly rising European poker star in recent years, known for his aggressive style and calm decision-making. Reaching heads-up in this WSOP high roller once again proves his strength. With this nearly $1.9 million prize, he will directly move up the global poker earnings leaderboard.
WSOP high rollers have always been battlegrounds where top players compete for glory and massive prizes. The $100,000 buy-in level typically features no-limit Texas Hold'em. While the number of participants is small, the prize pool is enormous, and competition is fierce. Mulder's ability to stand out in such an event demonstrates his competitiveness against world-class opponents.
The WSOP 2026 series is still ongoing, with multiple high rollers and the Main Event yet to come. Poker enthusiasts can follow official channels for more updates.
FAQ
- Runner-up, with a prize of $1,894,282.